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[aprssig] A math problem concerning Lat and Long

Wes Johnston wes at kd4rdb.com
Wed Oct 6 02:25:26 UTC 2004


For close in distances, I count 1 degree north-south as 69statute 
miles.... of course one degree east-west is subject to the COS of the 
latitude.  Entirely as a quick approximation, I average the two lat's 
and use that average in my COS(lat) x 69 miles x X number of degrees. 
 From there, it's Pythagorean Theorem.... z^2=x^2+y^2

Again, this is only for a close in approx... I have checked this method 
and it's good to <0.1 mile at 100 miles, which was good enough for me.

Wes

kb2scs at optonline.net wrote:
> Hi All
>          Could someone please give me a formula to solve the 
> following problem.
> 
> Given a known Latitude and Longitude you move for example 8 stature 
> miles due west and then move 8 stature miles due north.
> After moving this distance and direction what is your new Latitude 
> and Longitude?
> 
> Or put another way.
> 
> Draw a x and y axis on a pice of paper. The origin is 
> 49.8167N and 73.1333W
> what is the Latitude and Longitude of a point that is 8 miles due 
> west by 8 miles due north?
> 
> Let us hope we never witness the "Silence Of The Hams"
> 73 DE John  KB2SCS
>        E-Mail:            kb2scs at arrl.net
>        Web Page:     http://www.qsl.net/kb2scs
> 
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