[aprssig] A math problem concerning Lat and Long
Wes Johnston
wes at kd4rdb.com
Tue Oct 5 21:25:26 CDT 2004
For close in distances, I count 1 degree north-south as 69statute
miles.... of course one degree east-west is subject to the COS of the
latitude. Entirely as a quick approximation, I average the two lat's
and use that average in my COS(lat) x 69 miles x X number of degrees.
From there, it's Pythagorean Theorem.... z^2=x^2+y^2
Again, this is only for a close in approx... I have checked this method
and it's good to <0.1 mile at 100 miles, which was good enough for me.
Wes
kb2scs at optonline.net wrote:
> Hi All
> Could someone please give me a formula to solve the
> following problem.
>
> Given a known Latitude and Longitude you move for example 8 stature
> miles due west and then move 8 stature miles due north.
> After moving this distance and direction what is your new Latitude
> and Longitude?
>
> Or put another way.
>
> Draw a x and y axis on a pice of paper. The origin is
> 49.8167N and 73.1333W
> what is the Latitude and Longitude of a point that is 8 miles due
> west by 8 miles due north?
>
> Let us hope we never witness the "Silence Of The Hams"
> 73 DE John KB2SCS
> E-Mail: kb2scs at arrl.net
> Web Page: http://www.qsl.net/kb2scs
>
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