[aprssig] A funny packet story/joke (The KISS guys will get it)

[Zeff_Wheelock at harvardpilgrim.org]

My bad.  I was doing some very fuzzy math.  But I came up with the correct answer.  Does that count?
In any case the number it comes up to is 18.4 quintillion unique values.

Zeff Wheelock
Lotus Notes Administrator
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             Jason Winningham                                                                       
             <jdw at eng.uah.edu>                                                                      
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             11/10/2005 03:13 PM                 Re: [aprssig] A funny packet story/joke (The KISS  
                                                 guys will get it)                                  
                                                                                                    
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On Nov 10, 2005, at 2:03 PM, Zeff_Wheelock at harvardpilgrim.org wrote:

> Not to split hairs or anything:
>
>> Switching to 64 bit memory addresses will thus provide 4.2 billion
>> times 4.2 billion distinct
> locations.
>
> The actual math should be 4.2 billion x 4.2 billion + (4.2 billion x
> 4.2 billion).
>
> If I was to go from 6 bit to 12 bit, 6 bit would be 32, 12 bit is 2048.
> 32x32= 1024, so you are missing by 1024.  So the math would be
> 32x32+(32x32) to get the answer.

Sorry, but this is _completely_ wrong. The original poster was correct.

exponents add when you multiply. 2^32 * 2^ 32 = 2^(32+32) = 2^64

32 * 32 + 32 * 32 is nonsense.

12 bits give you 4096 unique values, not 2048.

-Jason
kg4wsv


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