[aprssig] MySQL difference in time

[Tom Hayward]

Subtraction then division?

( (unix now) - (unix then) ) / 3600 = elapsed hours

Maybe your problem is more complex than I understand it to be.

Tom KD7LXL

On Dec 21, 2007 1:45 AM, Andrew Rich <vk4tec at people.net.au> wrote:
>
>
> Anyone good at time calcs in perl ?
>
> I want to be able to say "It has been 7 hours 15 minutes" since we last
> heard XYZ
>
> Do I have to go back to unix time ?
>
>
>
> ----------------------------------------------------------------------------
> Andrew Rich VK4TEC
> vk4tec at people.net.au
> http://www.tech-software.net
>
>
>
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